if $$tan\theta =\frac{3}{5}$$ , $$0<\theta<90^\circ$$ then $$sin\theta cos\theta$$ is equal to:
Given,
$$tan\theta =\frac{3}{5}$$
From the triangle,
$$\text{Hypotenuse}^2=3^2+5^2$$
$$=$$>Â Hypotenuse =Â $$\sqrt{34}$$
$$\sin\theta\ =\frac{\text{Opposite side}}{\text{Hypotenuse}}=\frac{3}{\sqrt{34}}$$
$$\cos\theta\ =\frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{5}{\sqrt{34}}$$
$$\therefore\ \sin\theta\ \cos\theta\ =\frac{3}{\sqrt{34}}\times\frac{5}{\sqrt{34}}=\frac{15}{34}$$
Hence, the correct answer is Option D
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