If a > b > 0, AB = a - b cm, BC = $$2\sqrt{ab}$$ cm AC=a+b, then ∠ABC is
Solution
Now AB ^2 = a^2-2ab+b^2 (1) BC^2 =4ab (2) Adding 1 and 2 we get a^2+b^2+2ab Now this equals (a+b)^2= AC ^2 so we can say AB^2+BC^2=AC^2 So triangle ABC is a right triangle