If $$x+\frac{1}{x}=5$$, then the value of $$\frac{6x}{x^2+x+1}$$ is
Given : $$x+\frac{1}{x}=5$$
=> $$\frac{x^2+1}{x}=5$$
=> $$x^2+1=5x$$ -----------(i)
To find : $$\frac{6x}{x^2+x+1}$$
= $$\frac{6x}{5x+x}$$ Â Â [Using (i)]
= $$\frac{6x}{6x}=1$$
=> Ans - (A)
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