Question 66

If $$x+\frac{1}{x}=5$$, then the value of $$\frac{6x}{x^2+x+1}$$ is

Given : $$x+\frac{1}{x}=5$$

=> $$\frac{x^2+1}{x}=5$$

=> $$x^2+1=5x$$ -----------(i)

To find : $$\frac{6x}{x^2+x+1}$$

= $$\frac{6x}{5x+x}$$     [Using (i)]

= $$\frac{6x}{6x}=1$$

=> Ans - (A)

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