Chord AB of a circle when extended meets the tangent to the circle at point P. PT is the tangent touching the circle at point T. If lengths of PT and PB are 6 cm and 4 cm respectively, what is the length of PA?
Given : PT = 6 cm and PB = 4 cm
To find : PA = ?
Solution : Using properties of tangents, $$(PT)^2 = PA \times PB$$
=> $$(6)^2 = (PA) \times 4$$
=> $$PA = \frac{36}{4} = 9$$ cm
=> Ans - (D)
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