The lengths of the diagonals of a rhombus are 48 cm and 20 cm. What is the perimeter of the rhombus?
perimeter of the rhombus =Â $$2\times\ \sqrt{\ \left(diagonal_1\right)^2\ +\left(diagonal_2\right)^2}$$
=Â $$2\times\ \sqrt{\ \left(48\right)^2\ +\left(20\right)^2}$$
=Â $$2\times\ \sqrt{\ 2304\ +400}$$
= $$2\times\ \sqrt{\ 2704}$$
= $$2\times52$$
= 104 cm
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