Sign in
Please select an account to continue using cracku.in
↓ →
Pipes A and B can fill a tank in 8 hours and 12 hours respectively whereas pipe C can empty the full tank in 6 hours. A and B are opened for 3 hours and then closed and C is opened instantly. C will empty the tank in:
given information,
A fills a tank in 8 hours and B fills the same tank in 12 hours
where as C empty the same tank in 6 hours
so work done by A in one hour will be
A does 1 work in 8 hours so work done in 1 hour is $$\frac{1}{8}$$
similarly work done by B in one hour is $$\frac{1}{12}$$
work done by C in one hour $$\frac{1}{6}$$
therefore work done by A and B together in three hours is $$\frac{3}{8}$$ + $$\frac{3}{12}$$ = $$\frac{5}{8}$$
so time required by C to empty $$\frac{5}{8}$$ portion of tank is $$\frac{5}{8}\div\frac{1}{6}$$
= $$\frac{15}{4}$$
=3$$\frac{3}{4}$$
Create a FREE account and get: