Match List - I with List - II.

Choose the correct answer from the options given below :

First, recall the common disaccharides and polysaccharides along with the monosaccharide units or linkages that build them.

• Maltose = two $$\alpha$$-D-glucose units joined through an $$\alpha(1 \rightarrow 4)$$ glycosidic bond.
• Lactose = $$\beta$$-D-galactose + $$\beta$$-D-glucose joined by a $$\beta(1 \rightarrow 4)$$ bond.
• Sucrose = $$\alpha$$-D-glucose + $$\beta$$-D-fructose through an $$\alpha, \beta(1 \rightarrow 2)$$ bond.
• Cellulose = a long, unbranched polymer of $$\beta$$-D-glucose units linked by $$\beta(1 \rightarrow 4)$$ bonds.

Now match each species in List I with the corresponding description in List II.

Case A: Maltose
It consists of two glucose units → description (III).

Case B: Lactose
It is formed from galactose and glucose → description (I).

Case C: Sucrose
It contains glucose and fructose → description (IV).

Case D: Cellulose
It is a polymer having $$\beta(1 \rightarrow 4)$$-linked glucose units → description (II).

Hence the correct matching is
(A) → (III), (B) → (I), (C) → (IV), (D) → (II).

Option C which is: (A)-(III), (B)-(I), (C)-(IV), (D)-(II)