Question 66

If x=12 and y=4, then the value of $$(x+y)^\frac{x}{y}$$ is

$$x=12$$ and $$y=4$$

To find : $$(x+y)^\frac{x}{y}$$

= $$(12+4)^{\frac{12}{4}}$$

= $$(16)^3$$

= $$4096$$

=> Ans - (C)

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