Question 66
If the perimeter of a triangle is 28 cm and its inradius is 3.5 cm, what is its area?
Solution
$$ area of triangle = inradius \times semiperimeter $$
perimeter = 28
semiperimeter = $$ \frac{28}{2} = 14 $$
inradius = 3.5
$$ area = 3.5 \times 14 = 49 cm^2 $$
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