Solution
P($$P^{2}$$ + 3P + 3)
= P($$P^{2} + 4P + 3-P$$)
= P[$$(P+1)(P+3)-P)$$]
Given that P=99, Substituting it in above equation, we get
= 99[$$(99+1)(99+3)-99$$]
=99($$10200-99$$)
=99(10101)=999999
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