Solution
(a+b) = 6
Cubing both side,
$$\left(a+b\right)^3=6^3$$
$$a^3+b^3+3ab\left(a+b\right)=216$$
$$a^3+b^3+3\times\ \frac{16}{3}\times\ 6=216$$
$$a^3+b^3=216-96=120$$
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