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A heavy block of mass m is slowly placed on a conveyer belt moving with speed v. If coefficient of friction between block and the belt is $$\mu$$, the block will slide on the belt through distance
$$\frac{v}{\mu g}$$
$$\frac{v^2}{\sqrt{\mu g}}$$
$$\left(\frac{v}{\mu g}\right)^2$$
$$\frac{v^2}{2 \mu g}$$
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