Question 66

$$45-[38-(80\div4-(8-12\div3)\div4)]=?$$

Solution

$$45-[38-(80\div4-(8-12\div3)\div4)] = 45 - (38 - (20 - \dfrac{8-4}{4}))$$
$$= 45 - (38 -(20-\dfrac{4}{4})) = 45-(38-(20-1))$$
$$= 45-(38-19) = 45-19 = 26$$

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RRB ALP 31st Aug 2018 Shift-3

$$45-[38-(80\div4-(8-12\div3)\div4)]=?$$

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