Question 65
Two chords AB and CD ofa circle intersect at a point P inside the circle. If AB = 7 cm, PC = 2 cm and AP = 4 cm,then CD is equal to:
Solution
When two chords intersect at point P inside the circle then $$PA\times\ PB=PC\times\ PD$$
$$4\times3=PD\times2$$
$$PD=6$$
Therefore, CD= PC+PD=2+6=8 cm.
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