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Question 65
The mean of three numbers is 15. The range of this data set is 8 while the difference
between the two smallest numbers is 1. The greatest of the three numbers is:
Solution
Let the three numbers in ascending order be a,b and c
a+b+c=45
give range=8 i.e c-a=8
b-a=1
Substituting we get a+a+1+a+8=45
3a+9=45
3a=36
a=12
c=a+8
c=20
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