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The length and breadth of a rectangle are in the ratio 5 : 3. If the length is 8 m more than the breadth, what is the area of the rectangle?
Given,
The length and breadth of the rectangle are in the ratio 5 : 3
Let the length and breadth of the rectangle are 5p and 3p respectively
The length is 8 m more than the breadth
$$=$$> 5p = 3p +8
$$=$$> 5p - 3p = 8
$$=$$> 2p = 8
$$=$$> p = 4
$$\therefore\ $$Area of the rectangle = $$5p\times3p$$ = $$15p^2$$ = $$15\left(4\right)^2$$ = $$15\left(16\right)$$ = $$240m^2$$
Hence, the correct answer is Option B
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