Question 65

Of the 3 numbers whose average is 64, the first number is 1/3 times the sum of other 2. The first number is

Solution

Let the three numbers be $$x,y,z$$

Sum of three numbers = $$x + y + z = 64 \times 3 = 192$$

According to ques, => $$x = \frac{1}{3} \times (y + z)$$

=> $$x = \frac{1}{3} \times (192 - x)$$

=> $$3x = 192 - x$$

=> $$3x + x = 4x = 192$$

=> $$x = \frac{192}{4} = 48$$

=> Ans - (D)

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