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Solution
$$(a-b)^3 $$=$$a^3$$+Â $$3\times a^2\times b$$+$$3\times a\times b^2$$- $$b^3$$
$$(a-4)^3 $$=$$a^3$$+ $$3\times a^2\times 4$$+$$3\times a\times 4^2$$- $$b^3$$
$$a^3 - 12\times a^2 + 48\times a - 64$$
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