In $$\triangle$$ABC, AB = AC, and $$\angle$$BAC is 50$$^\circ$$. Then $$\angle$$ABC and $$\angle$$BCA are, respectively:

In $$\triangle$$ABC,  AB = AC

Angles opposite to equal sides in triangle are equal.

$$\Rightarrow$$ $$\angle$$BCA = $$\angle$$ABC

Let $$\angle$$ABC = $$\angle$$BCA = x

In $$\triangle$$ABC,

$$\angle$$ABC + $$\angle$$BCA + $$\angle$$BAC = 180$$^\circ$$

$$\Rightarrow$$  x + x + 50$$^\circ$$ = 180$$^\circ$$

$$\Rightarrow$$  2x = 130$$^\circ$$

$$\Rightarrow$$  x = 65$$^\circ$$

$$\therefore\ $$ $$\angle$$ABC = $$\angle$$BCA = 65$$^\circ$$

Hence, the correct answer is Option B