If the sum of the measures of all the interior angles of polygon is 1800°, find the number of sides of the polygon?
Let number of sides of the polygon = $$n$$
Sum of all interior angles of a polygon having $$n$$ sides = $$(n - 2) \times 180$$° = $$1800$$°
=> $$(n - 2) = \frac{1800}{180} = 10$$
=> $$n = 10 + 2 = 12$$
$$\therefore$$ The polygon having sum of interior angles 1800° has 12 sides
=> Ans - (A)
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