Question 64

A train crosses a platform 180 m long in 60 sec at a speed of 72 km/h. The time taken by the train to cross an electric pole is:

Solution

Length of platform = 180 m

Time = 60 sec

Speed = 72 km/hr = 72$$\times$$ 5/18 = 20 m/sec

Total length = length of platform + length of train = 180 + length of train

Speed = length/time

180 + length of train = 20 $$\times$$ 60

Length of train =1200 - 180 = 1020 m

The time taken by the train to cross an electric pole = 1020/20 = 51 sec

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