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Question 64
A mixture is composed of 11 parts of pure milk and 2 parts of water. If 35 litres of water were added to the mixture then the new mixture will contain twice as much pure milk as water, then how many litres of pure milk does the original mixture contain?
Solution
Let pure milk be 11x
Then water will be 2xÂ
Now when 35 liters of water is added we get water = 2x+35
Now as per condition 2(2x+35) =11x
4x+70 =11x
7x=70
x=10
So originial amount of pure milk = 10(11) =110
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