Question 64

A cricketer, whose bowling average was 12.4 runs/wicket takes 5 wickets for 22 runs in a match, thereby decreases his average by 0.4. The number of wickets, taken by him before this match was:

Solution

Let the number of wickets taken = $$x$$

Bowling average = 12.4

=> Total runs conceded by the bowler = $$12.4x$$

After the match, new bowling average = $$12.4-0.4=12$$

=> $$\frac{12.4x+22}{x+5}=12$$

=> $$12.4x+22=12x+60$$

=> $$12.4x-12x=60-22$$

=> $$0.4x=38$$

=> $$x=\frac{38}{0.4}=95$$

=> Ans - (C)

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