Question 63

The least number, which when divided by 5, 6, 7 and 8 leaves a remainder 3 in each case, but when divided by 9 leaves no remainder, is:

Solution

L.C.M. of 5, 6, 7 and 8 = 840

Thus, required number is of the form = $$840k+3$$

Least value of $$k$$ for which $$(840k+3)$$ is divisible by 9 is $$k=2$$

$$\therefore$$ Required number = $$840 \times 2+3=1683$$

=> Ans - (B)

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