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What is the volume of the sphere whose diameter is 42 cm?(Take $$\pi = \frac{22}{7}$$)
Diameter of the sphere = 42 cm
radius of the sphere = $$\frac{42}{2}$$ = 21 cm
volume of the sphere = $$\frac{4}{3}\times\ \pi\ \times\ \left(radius\right)^3$$
= $$\frac{4}{3}\times\frac{22}{7}\ \times\ \left(21\right)^3$$
= $$\frac{88}{21}\ \times\ \left(21\right)^3$$
= $$88\ \times\ \left(21\right)^2$$
= $$88\ \times\ 441$$
= 38808 $$cm^3$$
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