Given, 72k460k is divisible by 6.
72k460k is divisible by both 2 and 3.
So, k is even and sum of the digits is divisible by 3.
(7 + 2 + k + 4 + 6 + 0 + k =Â 19 + 2k) is divisible by 3.
since k is even, the only possibility is k = 4.
Hence, the correct answer is Option A
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