Question 63

In the given figure, $$\cos\theta$$ is equal to:

Solution

In $$\triangle$$PQR,

QR$$^2$$ + PR$$^2$$ = PQ$$^2$$

$$\Rightarrow$$ 12$$^2$$ + PR$$^2$$ = 13$$^2$$

$$\Rightarrow$$ 144 + PR$$^2$$ = 169

$$\Rightarrow$$ PR$$^2$$ = 25

$$\Rightarrow$$ PR = 5 units

$$\therefore\ $$ $$\cos\theta=\frac{\text{adjacent side}}{\text{hypotenuse}}=\frac{\text{PR}}{\text{PQ}}=\frac{5}{13}$$

Hence, the correct answer is Option A

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