Solution
In $$\triangle$$PQR,
QR$$^2$$ + PR$$^2$$ = PQ$$^2$$
$$\Rightarrow$$ 12$$^2$$ + PR$$^2$$ = 13$$^2$$
$$\Rightarrow$$ 144 + PR$$^2$$ = 169
$$\Rightarrow$$ PR$$^2$$ = 25
$$\Rightarrow$$ PR = 5 units
$$\therefore\ $$ $$\cos\theta=\frac{\text{adjacent side}}{\text{hypotenuse}}=\frac{\text{PR}}{\text{PQ}}=\frac{5}{13}$$
Hence, the correct answer is Option A
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