In the circuit arrangement shown two cells supply a current I to a load resistance $$R = 9\ \Omega$$. One cell has an emf $$E_1 = 9$$ V and internal resistance $$r_1 = 1\ \Omega$$ and the other cell has an emf $$E_2 = 6$$ V and internal resistance $$r_2 = 3\ \Omega$$. The currents are as shown. Then,

A

$$I_1 = 0.9$$ A and $$I_2 = 0.5$$ A

B

$$I \approx 0.85$$ A

C

if the cell of emf $$E_1$$ is removed, current I will be smaller

D

if the cell of emf $$E_2$$ is removed, current I will be smaller