Question 63

In a defective 6 faced die with numbers 1 to 6 inscribed,probability of odd is 2 times that of even. What is the probability to gt number 5 in single throw?

Solution

Prob of even + Prob of odd = 1 (total probability)

Prob of even + 2 (Prob of even) = 1

3(Prob of even) = 1

Prob of even = 1/3

So, prob of odd = 2/3

Since there are 3 odd numbers {1,3,5} .

So, Prob of getting 5 is 1/3

Hence, getting 5 ( odd ) in a single throw is = 2/3 * 1/3 = 2/9

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