Solution
Average of first $$n$$ even numbers = $$(n+1)$$ and average of first $$n$$ odd numbers = $$n$$
=> Average of first 10 even numbers = $$(10+1)=11$$
=> Ans - (C)
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Average of first $$n$$ even numbers = $$(n+1)$$ and average of first $$n$$ odd numbers = $$n$$
=> Average of first 10 even numbers = $$(10+1)=11$$
=> Ans - (C)
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