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N is increased successively by 12.5% and 16%. If N = 400, then what is the value of the increase?
N = 400
N is increased successively by 12.5% and 16%.
Number become after two successive increase = N of (100+12.5)% of (100+16)%
= 400 of 112.5% of 116%
= $$400\times\frac{9}{8}\times\frac{116}{100}$$
= $$1\times\frac{9}{2}\times116$$
= $$9\times58$$
= 522
The value of the increase = 522-400
= 122
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