Question 62

If x is the fourth proportional to 36, 48 and 15, and 4.2, y, 9 and 13.5 are in proportion, then the difference between y and x is:

Solution

$$x$$ is the fourth proportional to 36, 48 and 15.

=> $$\frac{36}{48}=\frac{15}{x}$$

=> $$x=\frac{48\times15}{36}=20$$

Also, $$\frac{4.2}{y}=\frac{9}{13.5}$$

=> $$y=\frac{4.2\times13.5}{9}=6.3$$

$$\therefore$$ $$(x-y)=20-6.3=13.7$$

=> Ans - (A)


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