If the sewage from a city is $$95 \times 10^{6}$$l/day and the average five day BOD is 300 mg/l ,the population equivalent of the city is :(assume 5 day BOD percapita at $$20^\circ C$$ = 0.075 kg/day

A

2,10,000

B

3,80,000

C

5,10,000

D

6,25,000