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If the sewage from a city is $$95 \times 10^{6}$$l/day and the average five day BOD is 300 mg/l ,the population equivalent of the city is :(assume 5 day BOD percapita at $$20^\circ C$$ = 0.075 kg/day
2,10,000
3,80,000
5,10,000
6,25,000
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