Question 62

If $$a=2b=8c$$ and $$a+b+c=13$$ then the value of $$\frac{\sqrt{a^{2}+b^{2}+c^{2}}}{2c}$$ is:

Solution

$$a+b+c=13$$

Put the value of a and b,

8c + 4c + 8c = 13

c = 13/20
On put the value of a, b and c,

$$\frac{\sqrt{(8c)^{2}+(4c)^{2}+c^{2}}}{2c}$$

$$\frac{\sqrt{81c^{2}}}{2c}$$ = $$\frac{9c}{2c}$$ = $$\frac{9}{2}$$

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