Question 62
If $$a=2b=8c$$ and $$a+b+c=13$$ then the value of $$\frac{\sqrt{a^{2}+b^{2}+c^{2}}}{2c}$$ is:
Solution
$$a+b+c=13$$
Put the value of a and b,
8c + 4c + 8c = 13
c = 13/20
On put the value of a, b and c,
$$\frac{\sqrt{(8c)^{2}+(4c)^{2}+c^{2}}}{2c}$$
$$\frac{\sqrt{81c^{2}}}{2c}$$ = $$\frac{9c}{2c}$$ = $$\frac{9}{2}$$
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