Question 61

In a circle, chords PQ and TS are produced to meet at R. If RQ = 14.4 cm, PQ = 11.2 cm, and SR = 12.8 cm, then the length of chord TS is:

Solution

From the property,

RQ $$\times RP = SR \times RT$$

14.4 $$\times (RQ + PQ) = 12.8 \times RT$$

14.4 $$\times (14.4 + 11.2) = 12.8 \times RT$$

368.14 = 12.8 $$\times RT$$

RT = 28.8 cm

RT = TS + SR

28.8 = 12.8 + TS

TS = 16 cm

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