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If a + b = 11 and $$a^2 + b^2$$ = 61, then value of ab is
Given : $$(a + b) = 11$$ and $$a^2 + b^2 = 61$$
Using $$(a + b)^2 = a^2 + b^2 + 2ab$$
=> $$(11)^2 = 61 + (2 \times ab)$$
=> $$2 ab = 121 - 61 = 60$$
=> $$ab = \frac{60}{2} = 30$$
=> Ans - (D)
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