Question 61

The Bar graph given below presents the amount (volume in litres) of water in ten different mixtures.

The amount of water in mixture M7 is how much more than the average amount of water per mixture?

Solution

The amount of water in mixture M7 = 28

avg = $$\frac{12+14 +15 + 17+21 +24+28+31+34+ 40}{10}$$ = 23.6 litre

so,

= avg - amount of water in mixture M7

= 28 - 23.6

= 4.4

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