Question 61

Study the following bar graph that shows the number of students enrolled for different courses in institute A and B during 5 years, and answer the question that follows.

The number of students enrolled in A during 2014, 2016 and 2018 is what percentage of the total number of average students enrolled in B during the 5 years (correct to one decimal place) ?

Solution

Total number of students enrolled in A during 2014, 2016 and 2018 are :

$$\therefore\ 160+300+360=720$$

Average = $$\frac{sum\ of\ observation}{number\ of\ observation}$$

Total number of average students enrolled in B during 5 years are :

$$\frac{\left(225+360+375+325+225\right)}{5}=\ \frac{1510}{5}=302$$

Required percentage = $$\frac{720}{302}\times\ 100=\ 238.4\%$$

Hence, Option A is correct

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