Question 62
What is the sume of the numbers between 300 and 500 such that when they are divided by 6, 12 and 16, it leaves no remainder?
Solution
LCM of 6, 12, 16 = 48
Multiple of 48 between 300 and 500 are as follows :
$$\therefore\ 336,\ 384,\ 432\ and\ 480$$
Required Sum = 336 + 384 + 432 + 480 = 1632
Hence, Option B is correct
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