Question 62

What is the sume of the numbers between 300 and 500 such that when they are divided by 6, 12 and 16, it leaves no remainder?

Solution

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LCM of 6, 12, 16 = 48

Multiple of 48 between 300 and 500 are as follows :

$$\therefore\ 336,\ 384,\ 432\ and\ 480$$

Required Sum = 336 + 384 + 432 + 480 = 1632

Hence, Option B is correct

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