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The average of six numbers is m and the arrange of three of these is y. If the average of the remining three is Z, then:
Sum of observations = Average * Number of observations.
Sum of all 6 numbers = 6m
Sum of 3 numbers = 3y and Sum of the remaining 3 numbers = 3Z.
equating the sum of all 6 numbers,
6m = 3y + 3Z
==> 2m = y +Β Z.
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