RRB NTPC 3 April 2016 2nd Shift

Question 60

Find $$\sin$$(90° - $$\theta)$$

Solution

We know that ,

Sin(A-B)=Sin(A)Cos(B)-Cos(A)Sin(B)

so,

$$Sin(90-\theta)$$

$$=Sin90Cos\theta-Cos90Sin\theta$$

$$=1×Cos\theta-0$$

(Sin90=1 and Cos90=0)

$$=Cos\theta.$$

D is correct choice.


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