Which of the following is the CORRECT option for the triangles having sides in the ratio of 3:4:6?
Let the sides of $$\triangle$$ ABC be $$a,b,c$$, where the largest side = $$'c'$$
If $$c^2=a^2+b^2$$, then the angle at $$C$$ is right angle.
If $$c^2<a^2+b^2$$, then the angle at $$C$$ is acute angle.
If $$c^2>a^2+b^2$$, then the angle at $$C$$ is obtuse angle.
Now, according to ques, => $$6^2=36$$
and $$3^2+4^2=9+16=25$$
$$\therefore c^2>a^2+b^2$$, hence it is an obtuse angled triangle.
=> Ans - (B)
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