The circle of radius 4 cm and centre O has a tangent PR. If $$\angle POR=90^\circ$$ and OR = 7 cm and OP = 24 cm. Calculate the length (in cm) of PR.
Given : $$\angle$$ POR = $$90^\circ$$ and OR = 7 cm and OP = 24 cm
To find : PR = ?
Solution : In right $$\triangle$$ OPR,
=> $$(PR)^2=(OP)^2+(OR)^2$$
=> $$(PR)^2=(24)^2+(7)^2$$
=> $$(PR)^2=576+49=625$$
=> $$PR=\sqrt{625}=25$$ cm
=> Ans - (C)
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