Question 6
In the triangle ABC, the internal bisector of angle A meets the side BC at D. If BD = 7.5 cm and BC = 9 cm. Then calculate the value of AB : AC.
Solution
Given : AD is the angle bisector of $$\angle$$ A. Also,  BD = 7.5 cm and BC = 9 cm
To find : AB : AC = ?
Solution : CD = 9 - 7.5 = 1.5 cm
According to angle bisector theorem,
=> $$\frac{AB}{BD}=\frac{AC}{DC}$$
=> $$\frac{AB}{AC}=\frac{BD}{DC}$$
=> $$\frac{AB}{AC}=\frac{7.5}{1.5}=\frac{5}{1}$$
=> Ans - (C)
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