A, B, C, D, E, F and G each have a different age. No one is older than D. The second oldest person is 32 years old. The second youngest person is 20 years old, and it is not E. Only threepeople are aged between B and D. A is younger than C but older than B. F is 7 years younger than C and is 25 years old. A is older than 25 years
Solution
D is the oldest.
2nd oldest is 32 yrs old.
2nd youngest person is 20 years old.
We can create an arrangement with decreasing ages as:
1 - D -
2 - - 32
3
4
5
6 - - 20
7
Only 3 people are aged between B and D which means that B is 5th oldest. F is 25 years old and A is elder than F. It implies that A is elder than atleast 4 people .i.e. 6th and 7th rankers, F and B.
A is also younger than C which leaves only 1 case where C is 2nd oldest, A is 3rd oldest and F is 4th oldest.
C = F + 7 = 25+7 = 32 years old.
1 - D -
2 - C - 32
3 - A -
4 - F - 25
5 - B -
6 - - 20
7 -
E is not the 2nd youngest person which means that E is the youngest and G is the 2nd youngest.
1 - D -
2 - C - 32
3 - A -
4 - F - 25
5 - B -
6 - G - 20
7 - E -
The 2nd youngest is G.
