Question 59

The value of $$\sin^2 38^\circ + \sin^2 52^\circ + \sin^2 30^\circ - \tan^2 45^\circ$$ is equal to:

Solution

$$\sin^2 38^\circ + \sin^2 52^\circ + \sin^2 30^\circ - \tan^2 45^\circ$$

$$\sin^2 38^\circ +\sin^2 (90-38)^\circ + \sin^2 30^\circ - \tan^2 45^\circ$$

$$\sin^2 38^\circ +\cos^2 38^\circ + \sin^2 30^\circ - \tan^2 45^\circ$$

$$1+\frac{1}{4}-1=\frac{1}{4}$$

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