Laplace transform of $$\sin^3 2t$$ is
$$\frac{24}{(s^2 + 4)(s^2 + 36)}$$
$$\frac{1}{(s^2 + 4)(s^2 + 64)}$$
$$\frac{48}{(s^2 + 4)(s^2 + 36)}$$
$$\frac{64}{(s^2 + 4)(s^2 + 36)}$$
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