Question 59

In an equilateral triangle ABC, D, E, F are the mid points of AB, BC and AC respectively. The quadrilateral BEFD is a

Given : In Triangle ABC, D,E and F are the mid points of sides AB, BC, CA respectively.

As we know that tiangle formed by joining the midpoint of an equilateral triangle is also a equilateral triangle

So, DE=EF=FD=EB=DB

Hence, BEFD is a rhombus.

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