If $$\left(2a+\frac{3}{a}-1\right)=11$$, what is the value of $$\left(4a^2 + \frac{9}{a^2}\right)?$$
$$\left(2a+\frac{3}{a}-1\right)=11$$
$$2a+\frac{3}{a}=12$$
$$4a^2+\frac{9}{a^2}+2.2a.\frac{3}{a}=144$$
$$4a^2+\frac{9}{a^2}+12=144$$
$$4a^2+\frac{9}{a^2}=132$$
Hence, the correct answer is Option C
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