Question 59

If $$\left(2a+\frac{3}{a}-1\right)=11$$, what is the value of $$\left(4a^2 + \frac{9}{a^2}\right)?$$

Solution

$$\left(2a+\frac{3}{a}-1\right)=11$$

$$2a+\frac{3}{a}=12$$

$$4a^2+\frac{9}{a^2}+2.2a.\frac{3}{a}=144$$

$$4a^2+\frac{9}{a^2}+12=144$$

$$4a^2+\frac{9}{a^2}=132$$

Hence, the correct answer is Option C


Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

cracku

Boost your Prep!

Download App