If $$x=1+\sqrt2+\sqrt3$$, then the value of $$x^2-2x-4$$ is
Given : $$x=1+\sqrt2+\sqrt3$$
=> $$x-1=\sqrt2+\sqrt3$$
Squaring both sides,
=> $$(x-1)^2=(\sqrt2+\sqrt3)^2$$
=> $$x^2+1-2x=2+3+2\sqrt6$$
=> $$x^2-2x+1-5=2\sqrt6$$
=> $$x^2-2x-4=2\sqrt6$$
=> Ans - (D)
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